coolhabhi wrote:Nine persons went to a hotel for taking their meals. Eight of them spent 12$ each on their meals and the ninth spent 8$ more than the average expenditure of all the nine. What was the total money spent by them.
A)115$
B)116$
C)117$
D)118$
E)119$
We can PLUG IN THE ANSWERS, which represent the total spent.
Since there are 9 people, the correct answer is probably a MULTIPLE OF 9.
For an integer to be a multiple of 9, the sum of its digits must be a multiple of 9.
Only
C -- 1+1+7 = 9 -- satisfies this constraint.
When the correct answer choice is plugged in, the first 8 people will spend $12 each.
Answer choice
C: 117
Average price per person = 117/9 = 13.
Since the 9th person spent $8 more than the average, price for the 9th person = 13+8 = 21.
Thus, the total for the first 8 people = 117-21 = 96.
Price for each of the first 8 people = 96/8 = 12.
Success!
The correct answer is
C.
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