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Tom travels the same distance in 4 steps as Alice travels in

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by Max@Math Revolution » Wed Jul 17, 2019 12:19 am
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[GMAT math practice question]

Tom travels the same distance in 4 steps as Alice travels in 5 steps. If the length of one of Alice’s steps is 36 cm, what distance, in cm, does Tom cover in 18 steps?

A. 5184
B. 3688
C. 1800
D. 1243
E. 810
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by GMATGuruNY » Wed Jul 17, 2019 3:04 am
Max@Math Revolution wrote:[GMAT math practice question]

Tom travels the same distance in 4 steps as Alice travels in 5 steps. If the length of one of Alice’s steps is 36 cm, what distance, in cm, does Tom cover in 18 steps?

A. 5184
B. 3688
C. 1800
D. 1243
E. 810
Since each of Alice's steps = 36 cm, the distance traveled by Alice in 5 steps = 5*36 = 180 cm.
Since Tom requires only 4 steps to travel this 180-cm distance, each of Tom's steps = 180/4 = 45 cm.
Thus, the distance traveled by Tom in 18 steps = 18*45 = 810 cm.

The correct answer is E.
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by Max@Math Revolution » Thu Jul 18, 2019 11:51 pm
=>

Let t and a be stride-lengths of Tom and Alice, respectively.
Then 4t = 5a and a = 36.
So, t = (5/4)a = (5/4)*36 = 45 cm.
It follows that 18t = 18*45 = 810 cm.

Therefore, E is the answer.
Answer: E
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