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Expert replies

vishubn: Legendary Member; Posts: 574; Joined: Sun Jun 01, 2008 8:48 am; Location: Bangalore; Thanked: 28 times

by vishubn » Mon Dec 22, 2008 6:56 am

If Pool Y currently contains more water than Pool X, and if Pool X is currently filled to 2/7 of its capacity, what percent of the water currently in Pool Y needs to be transferred to Pool X if Pool X and Pool Y are to have equal volumes of water?

(1) If all the water currently in Pool Y were transferred to Pool X, Pool X would be filled to 6/7 of its capacity.

(2) Pool X has a capacity of 14,000 gallons.

it toookk way too long

shortcuts??

KILL !! DIE !! or BEAT my FEAR !!! de@D END!!

Source: Beat The GMAT — Data Sufficiency | Mon Dec 22, 2008 6:56 am

mals24: Legendary Member; Posts: 683; Joined: Tue Jul 22, 2008 1:58 pmFollowed by: 2 members; Location: Dubai; Thanked: 73 times

by mals24 » Mon Dec 22, 2008 9:34 am

IMO A

Let the capacity of Pool X = X

Pool X = 2/7X filled.
To solve the question we just need to know the quantity of water in pool Y.

St1:

(1) If all the water currently in Pool Y were transferred to Pool X, Pool X would be filled to 6/7 of its capacity.

So after transferring the water from Y to X, quantity of water in pool X = 6/7
6/7-2/7 = 4/7, which is the quantity of water in pool Y.

So SUFF.

St2:

(2) Pool X has a capacity of 14,000 gallons.

We cant deduce anything about Pool Y from this information. INSUFF

So A.

vittalgmat: Legendary Member; Posts: 621; Joined: Wed Apr 09, 2008 7:13 pmFollowed by: 4 members; Thanked: 33 times

by vittalgmat » Mon Dec 22, 2008 1:12 pm

Thanks Mals,
that was elegent. Couldnt have thought a faster one.

ronniecoleman: Legendary Member; Posts: 546; Joined: Sun Nov 16, 2008 11:00 pm; Location: New Delhi , India; Thanked: 13 times

by ronniecoleman » Thu Dec 25, 2008 5:15 am

The only shortcut i think can be use of word percentage...

Since percentage is required generally options with concrete answers are out of scope.. ( i mean generally)

Now it is said that

Capacity of A is greater than B

B = 2/7 X

Now If we add all A to B it becomes 6/7 x

so A has 4/7x

now

Midpoint of 2 and 6 is 4

So Final volume will be 4/7 x in both the containers

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