Three gnomes and three elves sit down in a row of six chairs. If no gnome will sit next to another gnome and no elf will sit next to another elf, in how many different ways can the elves and gnomes sit?
A. 18
B. 36
C. 48
D. 72
E. 96
The OA is D.
I solved this PS question as follows,
Case 1: G E G E G E - Total ways = 3!*3! = 36
Case 2: E G E G E G - Total ways = 3!*3! = 36
Total ways of arrangements = 36 + 36 = 72
Option D.
Has anyone another strategic approach to solve this PS question? Regards!
A. 18
B. 36
C. 48
D. 72
E. 96
The OA is D.
I solved this PS question as follows,
Case 1: G E G E G E - Total ways = 3!*3! = 36
Case 2: E G E G E G - Total ways = 3!*3! = 36
Total ways of arrangements = 36 + 36 = 72
Option D.
Has anyone another strategic approach to solve this PS question? Regards!
