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This problem is driving me crazy...javascript:emoticon(':?:'

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Junior | Next Rank: 30 Posts
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by litteraround » Wed Jun 11, 2008 1:30 pm
Even though, I know it is pretty simple, I just can't wrap my head around
it. I have tried every which way, but no success. So, please give it a shot and let me know how its done...


If w>y, the average of x and y is z, and the average of z and x is w, what is the value of (x-w)/(w-y) = ?


Thanks!
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by netigen » Wed Jun 11, 2008 2:10 pm
(y+x)/2 = z -->EQ 1

(z+x)/2 = w ---> EQ2

from EQ2 --->

z+x = 2w
x- w = w-z
x- w = w-(x+y)/2 (subs for z from EQ 1)
2 (x-w) = 2w-x -y
2 (x-w) = w-y + (w-x)
2 (x-w) - (w-x) = w-y
2 (x-w) + (x-w) = w-y
3 (x-w) = w-y
(x-w)/(w-y) = 1/3
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Junior | Next Rank: 30 Posts
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by litteraround » Wed Jun 11, 2008 2:25 pm
Thanks a lot.
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