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Start the planThere are \(y\) different travelers who each have a choice of vacationing at one of \(n\) different destinations. What is the probability that all \(y\) travelers will end up vacationing at the same destination?
A. \(\dfrac1{n!}\)
B. \(\dfrac{n}{n!}\)
C. \(\dfrac1{n^y}\)
D. \(\dfrac{1}{n^{y-1}}\)
E. \(\dfrac{n}{y^n}\)
Answer: D
Source: Manhattan GMAT
A. \(\dfrac1{n!}\)
B. \(\dfrac{n}{n!}\)
C. \(\dfrac1{n^y}\)
D. \(\dfrac{1}{n^{y-1}}\)
E. \(\dfrac{n}{y^n}\)
Answer: D
Source: Manhattan GMAT
