BTGmoderatorDC wrote:There are n students in a class. Of them, k boys and k girls (including Harvey and Jessica) are selected for a dance performance in which students will dance in pairs of one boy and one girl. What is the probability that Harvey will be paired with Jessica?

(1) Other than Harvey, 5 boys are selected for the dance.

(2) 8 of the k boys are not selected for the dance.

OA A

Source: Veritas Prep

We know that out of k boys, Harvey and out of k girls, Jessica are selected for the dance performance.

Harvey can be paired with any of the k girls; among k ways, only one way is such that Harvey and Jessica are paired. Thus, the probability that Harvey will be paired with Jessica = 1/k.

Only statement 1 gives the value of k; k = 1 + 5 = 6. Sufficient.

The correct answer: A

Hope this helps!

-Jay
_________________
Manhattan Review GMAT Prep

Locations: New York | Hyderabad | Mexico City | Toronto | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.

BTGmoderatorDC wrote:There are n students in a class. Of them, k boys and k girls (including Harvey and Jessica) are selected for a dance performance in which students will dance in pairs of one boy and one girl. What is the probability that Harvey will be paired with Jessica?

(1) Other than Harvey, 5 boys are selected for the dance.

(2) 8 of the k boys are not selected for the dance.

OA A

Source: Veritas Prep

We know that out of k boys, Harvey and out of k girls, Jessica are selected for the dance performance.

Harvey can be paired with any of the k girls; among k ways, only one way is such that Harvey and Jessica are paired. Thus, the probability that Harvey will be paired with Jessica = 1/k.

Only statement 1 gives the value of k; k = 1 + 5 = 6. Sufficient.

The correct answer: A

Hope this helps!

-Jay
_________________
Manhattan Review GMAT Prep

Locations: New York | Hyderabad | Mexico City | Toronto | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.

BTGmoderatorDC wrote:There are n students in a class. Of them, k boys and k girls (including Harvey and Jessica) are selected for a dance performance in which students will dance in pairs of one boy and one girl. What is the probability that Harvey will be paired with Jessica?

(1) Other than Harvey, 5 boys are selected for the dance.

(2) 8 of the k boys are not selected for the dance.

OA A

Source: Veritas Prep

We know that out of k boys, Harvey and out of k girls, Jessica are selected for the dance performance.

Harvey can be paired with any of the k girls; among k ways, only one way is such that Harvey and Jessica are paired. Thus, the probability that Harvey will be paired with Jessica = 1/k.

Only statement 1 gives the value of k; k = 1 + 5 = 6. Sufficient.

The correct answer: A

Hope this helps!

-Jay
_________________
Manhattan Review GMAT Prep

Locations: New York | Hyderabad | Mexico City | Toronto | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.

BTGmoderatorDC wrote:There are n students in a class. Of them, k boys and k girls (including Harvey and Jessica) are selected for a dance performance in which students will dance in pairs of one boy and one girl. What is the probability that Harvey will be paired with Jessica?

(1) Other than Harvey, 5 boys are selected for the dance.

(2) 8 of the k boys are not selected for the dance.

OA A

Source: Veritas Prep

We know that out of k boys, Harvey and out of k girls, Jessica are selected for the dance performance.

Harvey can be paired with any of the k girls; among k ways, only one way is such that Harvey and Jessica are paired. Thus, the probability that Harvey will be paired with Jessica = 1/k.

Only statement 1 gives the value of k; k = 1 + 5 = 6. Sufficient.

The correct answer: A

Hope this helps!

-Jay
_________________
Manhattan Review GMAT Prep

Locations: New York | Hyderabad | Mexico City | Toronto | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.

BTGmoderatorDC wrote:There are n students in a class. Of them, k boys and k girls (including Harvey and Jessica) are selected for a dance performance in which students will dance in pairs of one boy and one girl. What is the probability that Harvey will be paired with Jessica?

(1) Other than Harvey, 5 boys are selected for the dance.

(2) 8 of the k boys are not selected for the dance.

OA A

Source: Veritas Prep

We know that out of k boys, Harvey and out of k girls, Jessica are selected for the dance performance.

Harvey can be paired with any of the k girls; among k ways, only one way is such that Harvey and Jessica are paired. Thus, the probability that Harvey will be paired with Jessica = 1/k.

Only statement 1 gives the value of k; k = 1 + 5 = 6. Sufficient.

The correct answer: A

Hope this helps!

-Jay
_________________
Manhattan Review GMAT Prep

Locations: New York | Hyderabad | Mexico City | Toronto | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.

BTGmoderatorDC wrote:There are n students in a class. Of them, k boys and k girls (including Harvey and Jessica) are selected for a dance performance in which students will dance in pairs of one boy and one girl. What is the probability that Harvey will be paired with Jessica?

(1) Other than Harvey, 5 boys are selected for the dance.

(2) 8 of the k boys are not selected for the dance.

OA A

Source: Veritas Prep

We know that out of k boys, Harvey and out of k girls, Jessica are selected for the dance performance.

Harvey can be paired with any of the k girls; among k ways, only one way is such that Harvey and Jessica are paired. Thus, the probability that Harvey will be paired with Jessica = 1/k.

Only statement 1 gives the value of k; k = 1 + 5 = 6. Sufficient.

The correct answer: A

Hope this helps!

-Jay
_________________
Manhattan Review GMAT Prep

Locations: New York | Hyderabad | Mexico City | Toronto | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.

BTGmoderatorDC wrote:There are n students in a class. Of them, k boys and k girls (including Harvey and Jessica) are selected for a dance performance in which students will dance in pairs of one boy and one girl. What is the probability that Harvey will be paired with Jessica?

(1) Other than Harvey, 5 boys are selected for the dance.

(2) 8 of the k boys are not selected for the dance.

OA A

Source: Veritas Prep

We know that out of k boys, Harvey and out of k girls, Jessica are selected for the dance performance.

Harvey can be paired with any of the k girls; among k ways, only one way is such that Harvey and Jessica are paired. Thus, the probability that Harvey will be paired with Jessica = 1/k.

Only statement 1 gives the value of k; k = 1 + 5 = 6. Sufficient.

The correct answer: A

Hope this helps!

-Jay
_________________
Manhattan Review GMAT Prep

Locations: New York | Hyderabad | Mexico City | Toronto | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.

BTGmoderatorDC wrote:There are n students in a class. Of them, k boys and k girls (including Harvey and Jessica) are selected for a dance performance in which students will dance in pairs of one boy and one girl. What is the probability that Harvey will be paired with Jessica?

(1) Other than Harvey, 5 boys are selected for the dance.

(2) 8 of the k boys are not selected for the dance.

OA A

Source: Veritas Prep

We know that out of k boys, Harvey and out of k girls, Jessica are selected for the dance performance.

Harvey can be paired with any of the k girls; among k ways, only one way is such that Harvey and Jessica are paired. Thus, the probability that Harvey will be paired with Jessica = 1/k.

Only statement 1 gives the value of k; k = 1 + 5 = 6. Sufficient.

The correct answer: A

Hope this helps!

-Jay
_________________
Manhattan Review GMAT Prep

Locations: New York | Hyderabad | Mexico City | Toronto | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.