There are 6 stores in town that had a total of 20 visitors on a particular day. However, only 10 people went shopping that day; some people visited more than one store. If 6 people visited exactly two stores each, and everyone visited at least one store, what is the largest number of stores anyone could have visited?
A. 6
B. 8
C. 5
D. 9
E. 2
The OA is C.
1 Person ---> 1 store = 1 visit. (as the question says that some people visited more than 1 store, meaning that there was at least 1 person who visited 1 store)
6 People ---> 2 store = 12 visit.
Remaining 3 People, to maximize the number of stores visited by an individual, we minimize the store visited by other 2.
So,
2 people ---> 1 store = 2 visit.
Total visit remaining = 20 -1-12-2 = 5 visit. (which is done by the last person).
Has anyone another strategic approach to solve this PS question? Regards!
A. 6
B. 8
C. 5
D. 9
E. 2
The OA is C.
1 Person ---> 1 store = 1 visit. (as the question says that some people visited more than 1 store, meaning that there was at least 1 person who visited 1 store)
6 People ---> 2 store = 12 visit.
Remaining 3 People, to maximize the number of stores visited by an individual, we minimize the store visited by other 2.
So,
2 people ---> 1 store = 2 visit.
Total visit remaining = 20 -1-12-2 = 5 visit. (which is done by the last person).
Has anyone another strategic approach to solve this PS question? Regards!
