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There are 2 ways to draw this PIC!

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by abcdefg » Tue Jul 21, 2009 7:12 am
Please see attached pics. Can someone please clarify for me? Thanks.
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by raghavsarathy » Tue Jul 21, 2009 7:34 am
IMO the figure towards the right is the correct one

In the figure to the left , Q is not to the east of P . It is "north-east" of P !

We aren't supposed to consider that..
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by ssmiles08 » Tue Jul 21, 2009 8:06 am
IMO both are wrong. PQ is a straight line. PR is also a straight line (R is the bottom point, P is the top point) and QR is the hypotenuse.

The best way to do it is keep point P stagnant, and make the other points revolve around it.

PQ = x
PR = y
QR = sqrt(x^2 + y^2)

You are driving QR and then PR which gives

sqrt(x^2 + y^2) + y

divide by z and you get your hours.
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by abcdefg » Tue Jul 21, 2009 9:55 am
so my mistake was that I missed the words "due east" meaning straight east?
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by ssmiles08 » Tue Jul 21, 2009 10:15 am
No, your east is right (in the second pic).

Its the north thats wrong. R is directly below P. Another version of saying is you are going south from P to R.

Points R and Q are connected by the hypotenuse.

-Hope that made sense.
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by abcdefg » Tue Jul 21, 2009 10:36 am
it said Q is y miles north of R. So both scenarios work for that condition.
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by ssmiles08 » Tue Jul 21, 2009 10:47 am
OOh yeah I kept reading as P is y miles due north of R.

IMO your second diagram is right then. I agree with raghavsarathy then.
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