There are 10 children in a company's day-care center, and a

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swerve: Legendary Member; Posts: 2604; Joined: Sun Oct 29, 2017 2:04 pmFollowed by: 6 members

by swerve » Tue Aug 06, 2019 12:40 pm

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There are 10 children in a company's day-care center, and a pair of children is to be selected to play a game. At most, how many different pairs are possible?

A. 100
B. 90
C. 50
D. 45
E. 25

The OA is D

Source: GMAT Prep

Source: Beat The GMAT — Problem Solving | Tue Aug 06, 2019 12:40 pm

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Jay@ManhattanReview: GMAT Instructor; Posts: 3008; Joined: Mon Aug 22, 2016 6:19 amFollowed by: 34 members; Location: Grand Central / New York; Thanked: 470 times

by Jay@ManhattanReview » Fri Aug 09, 2019 1:07 am

swerve wrote:There are 10 children in a company's day-care center, and a pair of children is to be selected to play a game. At most, how many different pairs are possible?

A. 100
B. 90
C. 50
D. 45
E. 25

The OA is D

Source: GMAT Prep

A pair of children means that we have to select 2 children out of 10. Thus, the number of different pairs possible = 10C2 = (10.9) / (1.2) = 45

The correct answer: D

Hope this helps!

-Jay
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Scott@TargetTestPrep: GMAT Instructor; Posts: 8246; Joined: Sat Apr 25, 2015 10:56 amFollowed by: 29 members; Location: Los Angeles, CA; Thanked: 43 times

by Scott@TargetTestPrep » Sun Aug 11, 2019 6:46 pm

swerve wrote:There are 10 children in a company's day-care center, and a pair of children is to be selected to play a game. At most, how many different pairs are possible?

A. 100
B. 90
C. 50
D. 45
E. 25

The OA is D

Source: GMAT Prep

The number of possible pairs is 10C2 = (10 x 9)/2! = 45.

Answer: D

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