x² - 1 < = 0 and x²- x - 2 > = 0, then x lies in the interval/set
A. (-1, 2)
B.(-1, 1)
C. (1, 2)
D. {-1}.
E. (1, -2)
A. (-1, 2)
B.(-1, 1)
C. (1, 2)
D. {-1}.
E. (1, -2)
Nice Ques.
Let us solve first eq.
x^2 - 1 =<0
assume eq as x^2 = 1, we get roots as -1 & 1
Divide number line three parts, namely x<-1, -1=<x<=1, x>1
the second section satisfies the equation.
Similarly divide number line into three parts x=<-1, -1<x<2, x>=2 for equation no.2
If you have a closer look, you will find that [spoiler]x=-1[/spoiler] is the only common point for both equations.
Thanks
