The sum of the heights of two high-rises is x feet. If the

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by BTGmoderatorDC » Sun Jul 22, 2018 3:00 am

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The sum of the heights of two high-rises is x feet. If the first high rise is 37 feet taller than the second, how tall will the second high rise be after they add an antenna with a height of z feet to the top?

A. (x+z)/2 + 37
B. 2x−(37+z)
C. (x−37)/2 + z
D. x/2 - 37 + z
E. (2x−37)/z

Source: Beat The GMAT — Problem Solving | Sun Jul 22, 2018 3:00 am

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by [email protected] » Sun Jul 22, 2018 9:21 am

Hi All,

We're told that the SUM of the heights of TWO high-rises is X feet and the first high rise is 37 feet taller than the second. We're asked how tall the second high rise would be after an antenna is added (with a height of Z feet) to the top. This question can be solved in a couple of different ways, including by TESTing VALUES.

IF.... the two high-rises have heights of 2 feet and 39 feet, respectively, then X = 2+39 = 41
and Z = 3
Then the second high-rise would be 2+3 = 5 feet tall.
Thus, we're looking for an answer that equals 5, when we use X=41 and Z=3. You'll find that most of the answers are far too big - and that there's only one answer that matches....

Final Answer: C

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Rich

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by Jeff@TargetTestPrep » Wed Jul 25, 2018 4:33 pm

BTGmoderatorDC wrote:The sum of the heights of two high-rises is x feet. If the first high rise is 37 feet taller than the second, how tall will the second high rise be after they add an antenna with a height of z feet to the top?

A. (x+z)/2 + 37
B. 2x−(37+z)
C. (x−37)/2 + z
D. x/2 - 37 + z
E. (2x−37)/z

We can let r = the height of the second high rise and so (r + 37) = the height of the first high rise; , thus:

r + r + 37 = x

2r + 37 = x

2r = x - 37

r = (x - 37)/2

So after adding the antenna, the second high rise is:

(x - 37)/2 + z feet tall

Answer: C

Jeffrey Miller
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