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The slope of a line containing points \((2, -3)\) and \((4, p)\) is \(-1.\) What is the value of \(p?\)

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by Vincen » Thu Jul 30, 2020 8:27 am
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The slope of a line containing points \((2, -3)\) and \((4, p)\) is \(-1.\) What is the value of \(p?\)

A. -6
B. -5
C. 1
D. 5
E. 12

[spoiler]OA=B[/spoiler]

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Re: The slope of a line containing points \((2, -3)\) and \((4, p)\) is \(-1.\) What is the value of \(p?\)

by Scott@TargetTestPrep » Wed Aug 05, 2020 10:16 am
Vincen wrote: ↑
Thu Jul 30, 2020 8:27 am
 The slope of a line containing points \((2, -3)\) and \((4, p)\) is \(-1.\) What is the value of \(p?\)

A. -6
B. -5
C. 1
D. 5
E. 12

[spoiler]OA=B[/spoiler]

Solution:

Using the slope formula (y2 - y1) / (x2 - x1), we have:

(p - (-3)) / (4 - 2) = -1

(p + 3) / 2 = -1

p + 3 = -2

p = -5

Answer: B

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