Gmat_mission wrote:The product of \(n\) consecutive integers equals \(P\). Which of the following is true for \(n \ge 2?\)

I. \(P\) is an even number
II. \(P\) is an odd number
III. \(P\) is positive

(A) I only
(B) II only
(C) III only
(D) I and II only
(E) II and III only

[spoiler]OA=A[/spoiler]

Source: Magoosh

Since there are at least two integers (given that n ≥ 2), the product of n integers must be even (we have at least one 2 in P). So, Statement I is correct, therefore, Statement II is incorrect.

Statement III is not must be true. Let's take an example: Say, the n consecutive integers are -3, - 2 and - 1; thus, P = -6, not positive.

The correct answer: A

Hope this helps!

-Jay
_________________
Manhattan Review GMAT Prep

Locations: GRE Manhattan | ACT Tutoring Houston | SAT Prep Courses Seattle | Charlotte IELTS Tutoring | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.

Gmat_mission wrote:The product of \(n\) consecutive integers equals \(P\). Which of the following is true for \(n \ge 2?\)

I. \(P\) is an even number
II. \(P\) is an odd number
III. \(P\) is positive

(A) I only
(B) II only
(C) III only
(D) I and II only
(E) II and III only

[spoiler]OA=A[/spoiler]

Source: Magoosh

If P is the product of at least two consecutive integers, then at least 1 of the integers is even, and thus P must be even, so I is true. Furthermore, since P is even, it cannot be odd, so II is false. We also cannot say for sure whether P is positive. For example, if one of the integers is 0, then P = 0, which is not positive, so III is false.

Answer: A

Gmat_mission wrote:The product of \(n\) consecutive integers equals \(P\). Which of the following is true for \(n \ge 2?\)

I. \(P\) is an even number
II. \(P\) is an odd number
III. \(P\) is positive

(A) I only
(B) II only
(C) III only
(D) I and II only
(E) II and III only

[spoiler]OA=A[/spoiler]

Source: Magoosh

If P is the product of at least two consecutive integers, then at least 1 of the integers is even, and thus P must be even, so I is true. Furthermore, since P is even, it cannot be odd, so II is false. We also cannot say for sure whether P is positive. For example, if one of the integers is 0, then P = 0, which is not positive, so III is false.

Answer: A