The outside of the rectangular box represented in the figure

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AAPL: Moderator; Posts: 2749; Joined: Sun Oct 29, 2017 2:08 pmFollowed by: 2 members

by AAPL » Sat May 04, 2019 3:05 am

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The outside of the rectangular box represented in the figure above is to be decorated by attaching pieces of wrapping paper to cover all surfaces except the bottom of the box. What is the minimum number of square inches of wrapping paper needed?

A. 375
B. 600
C. 725
D. 800
E. 1250

OA B

Source: Beat The GMAT — Problem Solving | Sat May 04, 2019 3:05 am

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ceilidh.erickson: GMAT Instructor; Posts: 2095; Joined: Tue Dec 04, 2012 3:22 pmFollowed by: 247 members; Thanked: 1443 times

by ceilidh.erickson » Sat May 04, 2019 1:56 pm

If we want the minimum amount of wrapping paper, we want to know the SURFACE AREA of all surface except the bottom surface. Calculate each:

Top surface area = 25 x 10 = 250
2 sides of 5 x 10 = 2(5*10) = 100
2 sides of 5 x 25 = 2(5*25) = 250

250 + 100 + 250 = 600

The answer is B.

Ceilidh Erickson
EdM in Mind, Brain, and Education
Harvard Graduate School of Education

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Scott@TargetTestPrep: GMAT Instructor; Posts: 8246; Joined: Sat Apr 25, 2015 10:56 amFollowed by: 29 members; Location: Los Angeles, CA; Thanked: 43 times

by Scott@TargetTestPrep » Mon May 13, 2019 5:36 pm

AAPL wrote:GMAT Prep

The outside of the rectangular box represented in the figure above is to be decorated by attaching pieces of wrapping paper to cover all surfaces except the bottom of the box. What is the minimum number of square inches of wrapping paper needed?

A. 375
B. 600
C. 725
D. 800
E. 1250

OA B

The top face has an area of 25 x 10 = 250 sq. in.

The front and back faces have a total area of (25 x 5) x 2 = 250 sq. in.

The right and left faces have a total area of (10 x 5) x 2 = 100 sq. in.

Therefore, we need 250 + 250 + 100 = 600 sq. in. of wrapping paper.

Answer: B

Scott Woodbury-Stewart
Founder and CEO
[email protected]

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