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The main ingredient in a certain prescription drug capsule

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by AAPL » Wed Jul 31, 2019 7:44 am
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The main ingredient in a certain prescription drug capsule cost $500 per kilogram. If each capsule contains 600 milligrams of ingredient, what is the cost of the ingredient in a capsule? (1-kilogram \(= 10^6\) milligrams)

A. $0.30
B. $0.83
C. $1.20
D. $3.00
E. $3.33

OA A
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by swerve » Wed Jul 31, 2019 12:15 pm
Find the cost per mg, and multiply that by 600 mg.

1kg \(= 1\cdot 10^6\) mg. Cost per kg \(= \$500\). Therefore cost per mg \(= \frac{500}{10^6} = \frac{5}{10^4}\).

Multiply this by 600 to get cost per 600mg \(= \frac{5}{10^4}\cdot 6\cdot 10^2 = 30\cdot 10^{-2} = 0.3\)
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by Scott@TargetTestPrep » Mon Aug 05, 2019 4:11 pm
AAPL wrote:GMAT Prep

The main ingredient in a certain prescription drug capsule cost $500 per kilogram. If each capsule contains 600 milligrams of ingredient, what is the cost of the ingredient in a capsule? (1-kilogram \(= 10^6\) milligrams)

A. $0.30
B. $0.83
C. $1.20
D. $3.00
E. $3.33

OA A
We can use a proportion to solve this problem. Letting x be the cost, in dollars, per 600-mg capsule, we have:

$500/1 kg = $x/600 mg

Before we can cross multiply, we need the denominators to have the same units. Since we are given 1 kg = 10^6 mg, we have:

$500/10^6 mg = x/600 mg

500/10^6 = x/600

(10^6)(x) = 500(600)

1,000,000(x) = 300,000

10x = 3

x = 0.3

Thus, the cost is $0.30 per capsule.

Answer: A

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