BTGmoderatorLU wrote: ↑

Thu Feb 11, 2021 10:36 am

Source: Official Guide

The hard drive, monitor, and printer of a certain desktop computer system cost a total of $2,500. The cost of the printer and monitor together is equal to 2/3 of the cost of the hard drive. If the cost of the printer is $100 more than the cost of the monitor, what is the cost of the printer?

A. $800
B. $600
C. $550
D. $500
E. $350

The OA is C

Solution:

We can let H, M, and P be the price of the hard drive, monitor, and printer, respectively. Based on the information given, we can create the equations:

H + M + P = 2,500,

M + P = (2/3)H,

and

P = M + 100

We can substitute (2/3)H for M + P in the first equation and obtain:

H + (2/3)H = 2,500

3H + 2H = 7,500

5H = 7,500

H = 1,500

So we have M + P = (2/3)(1,500) = 1,000 and hence M = 1,000 - P. Substituting this into the third equation, we have:

P = 1,000 - P + 100

2P = 1,100

P = 550

Answer: C