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The Fig Newton

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by sanju09 » Sat Sep 25, 2010 12:16 am
Is x > y/z?

[1] x z > y.

[2] x^2 > y/z.


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by this_time_i_will » Sat Sep 25, 2010 12:34 am
is it E?
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by sanju09 » Sat Sep 25, 2010 1:07 am
this_time_i_will wrote:is it E?
on what grounds?
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by saurabhmahajan » Sat Sep 25, 2010 1:25 am
IMO: A

xz>y
solving inequality : x>y/z
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by sanju09 » Sat Sep 25, 2010 2:19 am
saurabhmahajan wrote:IMO: A

xz>y
solving inequality : x>y/z
but the OA is E
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by selfmade » Mon Sep 27, 2010 12:02 pm
Hi Sanju

Lets consider Option 1

xz > y

In the inequality problems , when we multiply or divide by any number, we need to consider whether the number is positive or negative.
Ex. In the above equation xz >y
If we divide both sides by z , it can result in x > y/z or x<y/z based on whether z>0 or z<0

So thgis statement is not sufficient to find if x> y/z

Lets consider option 2

x^2 > y/z
Taking squareroots, we get
x > + sqrt (y/z) or
x > - sqrt (y/z)

We dont have sufficient information to find if x > y/z

Combining both statements doesnt help as well

IMO E

Hope this helps
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by sanju09 » Mon Sep 27, 2010 10:54 pm
selfmade wrote:Hi Sanju

Lets consider Option 1

xz > y

In the inequality problems , when we multiply or divide by any number, we need to consider whether the number is positive or negative.
Ex. In the above equation xz >y
If we divide both sides by z , it can result in x > y/z or x<y/z based on whether z>0 or z<0

So thgis statement is not sufficient to find if x> y/z

Lets consider option 2

x^2 > y/z
Taking squareroots, we get
x > + sqrt (y/z) or
x > - sqrt (y/z)

We dont have sufficient information to find if x > y/z

Combining both statements doesnt help as well

IMO E

Hope this helps
--Arati
Hi Arati (or Aarti?),

We are not provided with options in DS, those are rather known as statements perhaps; and if x^2 > y/z, then

taking squareroots, we get

x > + sqrt (y/z) or

x < - sqrt (y/z)

...and why combining both statements doesnt help as well? Please throw some light
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