The average (arithmetic mean) of x, y, and z is 50. What is

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BTGmoderatorDC: Moderator; Posts: 7187; Joined: Thu Sep 07, 2017 4:43 pmFollowed by: 23 members

by BTGmoderatorDC » Tue Aug 13, 2019 4:42 pm

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The average (arithmetic mean) of x, y, and z is 50. What is the sum of (4x + y), (3y + z), and (3z)?

A. 150
B. 200
C. 600
D. 800
E. It cannot be determined from theinformation given.

OA C

Source: Princeton Review

Source: Beat The GMAT — Problem Solving | Tue Aug 13, 2019 4:42 pm

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Jay@ManhattanReview: GMAT Instructor; Posts: 3008; Joined: Mon Aug 22, 2016 6:19 amFollowed by: 34 members; Location: Grand Central / New York; Thanked: 470 times

by Jay@ManhattanReview » Tue Aug 13, 2019 8:54 pm

BTGmoderatorDC wrote:The average (arithmetic mean) of x, y, and z is 50. What is the sum of (4x + y), (3y + z), and (3z)?

A. 150
B. 200
C. 600
D. 800
E. It cannot be determined from theinformation given.

OA C

Source: Princeton Review

Given that the average (arithmetic mean) of x, y, and z is 50, we have (x + y + z) = 150.

Sum of (4x + y), (3y + z), and (3z) = 4x + y + 3y + z + 3z = 4x + 4y + 4z = 4(x = y + z) = 4*150 = 600.

The correct answer: C

Hope this helps!

-Jay
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Scott@TargetTestPrep: GMAT Instructor; Posts: 8246; Joined: Sat Apr 25, 2015 10:56 amFollowed by: 29 members; Location: Los Angeles, CA; Thanked: 43 times

by Scott@TargetTestPrep » Sun Aug 18, 2019 6:13 pm

BTGmoderatorDC wrote:The average (arithmetic mean) of x, y, and z is 50. What is the sum of (4x + y), (3y + z), and (3z)?

A. 150
B. 200
C. 600
D. 800
E. It cannot be determined from theinformation given.

OA C

Source: Princeton Review

We see that x + y + z = 50(3) = 150. Therefore,

(4x + y) + (3y + z) + (3z) = 4x + 4y + 4z = 4(x + y + z) = 4(150) = 600

Answer: C

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