The average American spends y dollars on food per month,

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AAPL: Moderator; Posts: 2749; Joined: Sun Oct 29, 2017 2:08 pmFollowed by: 2 members

by AAPL » Thu Jul 04, 2019 5:50 pm

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The average American spends y dollars on food per month, except during January, when food purchases are x percent lower than they are in other months. Which of the following represents food purchases, in dollars, for the first 9 months of a year?

A. $9y – \frac{xy}{100}$

B. $9y + xy$

C. $9y – xy$

D. $\frac{9y-xy}{9}$

E. $\frac{y-xy}{6}$

OA A

Source: Beat The GMAT — Problem Solving | Thu Jul 04, 2019 5:50 pm

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Ian Stewart: GMAT Instructor; Posts: 2623; Joined: Mon Jun 02, 2008 3:17 amFollowed by: 355 members; Location: Montreal; Thanked: 1090 times; GMAT Score:780

by Ian Stewart » Sat Jul 06, 2019 4:31 am

AAPL wrote: The average American spends y dollars on food per month, except during January, when food purchases are x percent lower than they are in other months. Which of the following represents food purchases, in dollars, for the first 9 months of a year?

Whose food purchases? As the question is written, it's impossible to tell what they're asking for. Assuming they mean to ask about the spending of an average American: with no discount, they'd spend $9y in nine months. They save x% in one month, so save (x/100)y = xy/100 dollars in one month. So the answer is 9y - xy/100 dollars.

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deloitte247: Legendary Member; Posts: 2214; Joined: Fri Mar 02, 2018 2:22 pmFollowed by: 5 members

by deloitte247 » Sat Jul 06, 2019 7:19 am

Question: Which of the following represents food purchases in dollar for the first 9 months of a year?

The average American, spent $y on food per month,
In January, Food purchases are x% lower than other months.
$$x\ \%\ y=\frac{x}{100}\cdot\frac{y}{1}=\frac{xy}{100}$$
$$Then,\ January\ food\ purchase=y-\frac{xy}{100}$$
So, food purchase for the first 9 months of a year,
$$January;\ y-\frac{xy}{100}$$ $$other\ 8\ months=y$$ $$Total\ \cos t=y-\frac{xy}{100}+\left(8y\right)$$

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