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Test Code 52, Section 6, Question 11

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by irfan_m1973 » Wed Dec 02, 2009 1:44 am
Image
(Click to Enlarge Image)

The figure above shows the dimensions of an isosceles triangle in terms of x. What is the area of the triangle?

(A) 24
(B) 30
(C) 48
(D) 60
(E) 96

Answer is C.

Explain please.
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by Stuart@KaplanGMAT » Wed Dec 02, 2009 2:30 am
irfan_m1973 wrote:Image
(Click to Enlarge Image)

The figure above shows the dimensions of an isosceles triangle in terms of x. What is the area of the triangle?

(A) 24
(B) 30
(C) 48
(D) 60
(E) 96

Answer is C.

Explain please.
We know that it's an isosceles triangle, therefore we know that:

2x - 2 = 3x - 8

since those two sides must be equal.

So we solve that equation to get:

x = 6

Now we know that the height is 6 and the base is 3x - 2 = 18 - 2 = 16

Area = (1/2)*base*height
Area = (1/2)*16*6 = 8*6 = 48... choose C.
Image

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by irfan_m1973 » Wed Dec 02, 2009 5:53 am
Stuart Kovinsky wrote:
irfan_m1973 wrote:Image
(Click to Enlarge Image)

The figure above shows the dimensions of an isosceles triangle in terms of x. What is the area of the triangle?

(A) 24
(B) 30
(C) 48
(D) 60
(E) 96

Answer is C.

Explain please.
We know that it's an isosceles triangle, therefore we know that:

2x - 2 = 3x - 8

since those two sides must be equal.

So we solve that equation to get:

x = 6

Now we know that the height is 6 and the base is 3x - 2 = 18 - 2 = 16

Area = (1/2)*base*height
Area = (1/2)*16*6 = 8*6 = 48... choose C.
Thank you so much Stuart. You made it look so easy !
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by aspirant1 » Wed Dec 02, 2009 9:56 pm
Stuart.....you have made this so easy. thanks a lot
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