terminator pq

answer is B

tarun.kirla wrote:If a, b, c, d and e are integers and p = 2a3b and q = 2c3d5e, is p

q a terminating decimal?




(1) a > c

(2) b > d

Hi,

Could you please check the question...I think there is something wrong with it.

sorry
its p= 2^a3^b
q= 2^c3^d5^e

tarun.kirla wrote:sorry
its p= 2^a3^b
q= 2^c3^d5^e

Still something wrong with it. Is it p/q or pq?

sorry its p/q

tarun.kirla wrote:sorry its p/q

1 is insuff as it depends on power of 3
1/3 is nonterminating
and we dnt know abt b and d

2 is suff as 3 in den gets cancelled out

p= 2^a3^b
q= 2^c3^d5^e

IMO: C

any thing divide by 5^e is always a terminating decimal

as p/q = 2^(a-c) x 3^(b-d) / 5^e

since a-c and b-d is positive, 2x3 / 5^e is terminatig

It should be B.

From(1), (a-c) is positive. But there is no information about b & d. It can be a terminating decimal or not depending on whether (b-d) is positive or not. So INSUFFICIENT.

From(2): (b-d) is positive. Now whether a-c is positive or not doesn't matter as it will always be a terminating decimal, given the condition 2. ence, SUFFICIENT.

So, the answer should be B.

true, Its B

aks.anupam wrote:It should be B.

From(1), (a-c) is positive. But there is no information about b & d. It can be a terminating decimal or not depending on whether (b-d) is positive or not. So INSUFFICIENT.

From(2): (b-d) is positive. Now whether a-c is positive or not doesn't matter as it will always be a terminating decimal, given the condition 2. ence, SUFFICIENT.

So, the answer should be B.