Tammie has 10 cards numbered 1 through 10. If she deals two to Tarrell without replacing any of them, what is the

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BTGmoderatorDC: Moderator; Posts: 7187; Joined: Thu Sep 07, 2017 4:43 pmFollowed by: 23 members

by BTGmoderatorDC » Mon Jan 18, 2021 4:49 pm

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Tammie has 10 cards numbered 1 through 10. If she deals two to Tarrell without replacing any of them, what is the probability that Tarrell will get both a 2 and a 3?

A. 1/5
B. 1/45
C. 1/50
D. 1/90
E. 14/45

OA B

Source: Princeton Review

Source: Beat The GMAT — Problem Solving | Mon Jan 18, 2021 4:49 pm

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Re: Tammie has 10 cards numbered 1 through 10. If she deals two to Tarrell without replacing any of them, what is the

by Scott@TargetTestPrep » Sun Jan 24, 2021 5:47 am

BTGmoderatorDC wrote: ↑
Mon Jan 18, 2021 4:49 pm
Tammie has 10 cards numbered 1 through 10. If she deals two to Tarrell without replacing any of them, what is the probability that Tarrell will get both a 2 and a 3?

A. 1/5
B. 1/45
C. 1/50
D. 1/90
E. 14/45

OA B

Solution:

The probability Tarrell will get a 2 followed by a 3 is 1/10 x 1/9 = 1/90. Similarly, the probability Tarrell will get a 3 followed by a 2 is also 1/10 x 1/9 = 1/90. Therefore, the probability that Tarrell will get both a 2 and a 3 (in any order) is 1/90 + 1/90 = 1/45.

Answer: B

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