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by ifthyder » Thu Oct 09, 2008 7:17 pm
what apprach one is supposed to follow ?
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by cramya » Thu Oct 09, 2008 7:27 pm
It must be C) 16

OA?
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by wizardofwashington » Thu Oct 09, 2008 7:55 pm
I agree with C ($16)
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by stop@800 » Thu Oct 09, 2008 10:45 pm
cramya wrote:It must be C) 16

OA?
have you considered both the possibilities?
I mean do we have any logic [when paths are more]?
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by raunekk » Fri Oct 10, 2008 1:59 am
imo:C $16
i cannt think of ne logic over here,,


n i dont think ther is ne other possibility,,,
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by kris610 » Fri Oct 10, 2008 7:39 am
You may use permutation here:

AECFA and AEFCA are the only possibilities as A to E and the final destination are fixed. The middle two values may be permuted to obtain the two possibilities, of which 16 is a minimum.
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by vishubn » Sat Oct 11, 2008 6:39 am

PostPosted: Thu Oct 09, 2008 11:45 pm Post subject:
cramya wrote:
It must be C) 16

OA?


have you considered both the possibilities?
I mean do we have any logic [when paths are more]?

same here the option which is poping up is just two ! i go with others !!

AECFA=16$
AEFCA=20$

so 16 is the answer

Vishu
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by earth@work » Sat Oct 11, 2008 1:28 pm
stop@800 wrote:
cramya wrote:It must be C) 16

OA?
have you considered both the possibilities?
I mean do we have any logic [when paths are more]?
It's 16$....that's the cheapest...i tried using more paths but they fall expensive...AECFA is the cheapest.
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