svx

There is something wrong here...we can combine both X and V but we still can not decide whether svx < 0 since we dont know the sign of S

and in the question stem it is given as (s^4), so it be will be POSITIVE in every case. Am I missing something here ?

Source of this question please.. the OA can't be C. Like logitech says - we don't have the sign for S and more over v < 0 imples x>0 and x>0 implies v<0.

We dont even need the statements to know v is positive and x is negative or vice versa (may be which one is which we need the staements but it makes no difference in determining the sign of svx - one of the three variables is positive and the 2nd one of the three negative)

(s^4) (v^3) (x^7) < 0

s^4 always positive. Either v is negative , x is postive or vice versa.So we need info on s.

The question seems a little weird.

Sogmat, can u please check if everything is right?

we can write ((svx)^3)s(x^4)<0
this means ((svx)^3)s<0 as x^4 is always positive

now if v<0 and x>0 implies vx<0

in anycase whether s<0 or s>0 the product will always be less than 0

(positive*negtative)^3*positive => negative*positive which is less than 0
(negative*negative)^3*positive => positive*negative which is also less than 0

so answer should be C

rahulg83 wrote:we can write ((svx)^3)s(x^4)<0
this means ((svx)^3)s<0 as x^4 is always positive

now if v<0 and x>0 implies vx<0

in anycase whether s<0 or s>0 the product will always be less than 0

(positive*negtative)^3*positive => negative*positive which is less than 0
(negative*negative)^3*positive => positive*negative which is also less than 0

so answer should be C

If (s^4) (v^3) (x^7) < 0, is svx < 0?
(1) v < 0
(2) x > 0

S = +2
V = -3
X = +1

SVX = -6


S=-2
V=-3
X=+1

SVX =+6

whats the source ?

IMO E

We need to know the value of S to determine svx < 0