BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

sum

Expert replies
by shashank.ism » Tue Feb 09, 2010 1:17 pm
If the sum of five consecutive positive integers is A, then the sum of the next five consecutive integers in terms of A is:

A+1
A+5
A+25
2A
5A
My Websites:
www.mba.webmaggu.com - India's social Network for MBA Aspirants

www.deal.webmaggu.com -India's online discount, coupon, free stuff informer.

www.dictionary.webmaggu.com - A compact free online dictionary with images.

Nothing is Impossible, even Impossible says I'm possible.
Join the discussion
Source: — Problem Solving |

by abhi332 » Tue Feb 09, 2010 3:51 pm
Let A= A1+A2+A3+A4+A5

if we want to add 5 more consecutive numbers then

Sum of the next five consecutive integers = (A1+5)+(A2+5)+(A3+5)+(A4+5)+(A5+5)

Sum = A1+A2+A3+A4+A5 +25

Sum = A +25
Join the discussion

by jeffedwards » Tue Feb 09, 2010 4:45 pm
shashank.ism wrote:If the sum of five consecutive positive integers is A, then the sum of the next five consecutive integers in terms of A is:

A+1
A+5
A+25
2A
5A
When it doubt just plug in numbers:

1+2+3+4+5 = 15 (or A)
5+7+8+9+10 = 40 (or A+25)
40-15=25

A+25 is your answer

Another hint, don't add the numbers to get the total. Just pick the middle number in each set and times that number by five.
Join the discussion