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sum of P

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by gmatmachoman » Sun May 02, 2010 5:46 am
If p is the smallest positive integer such that (p^3)/3920 is also an integer, what is the sum of the digits of p?

(A) 5 (B) 7 (C) 9 (D) 11 (E) 13
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Source: — Problem Solving |

by liferocks » Sun May 02, 2010 5:58 am
3920=8*490=2^3*7^2*5*2

hence p=2*7*5*2=140

ans 1+4+0=5..option A
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