g.shankaran wrote:the sum of the first 50 +ve even integers is 2550. which is the sum of the even integers from 102 to 200 inclusive?
1. 5100
2. 7550
3. 10100
4. 15500
5. 20100
To determine the sum of evenly spaced integers, use the following formula:
Sum = (number of integers) * (average of biggest and smallest)
To count the number of evenly spaced integers in a set:
Number of integers = (Biggest - Smallest)/(distance between each successive pair) + 1
With even integers, the distance between each successive pair is 2.
Thus, given the even integers from 102 to 200, inclusive:
Number of integers = (200-102)/2 + 1 = 50.
Average of biggest and smallest = (200+102)/2 = 151.
Sum = number * average = 50*151 = 7550.
The correct answer is
B.
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