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Steve traveled..........

Expert replies
by pzazz12 » Fri Oct 22, 2010 3:43 am
Steve traveled the first 2 hours of his journey at 40 mph and the remaining 3 hours of his journey at 80 mph. What is his average speed for the entire journey?

A. 60 mph
B. 56.67 mph
C . 53.33 mph
D. 64 mph
E. 66.67 mph
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Source: — Problem Solving |

by Rahul@gurome » Fri Oct 22, 2010 4:16 am
pzazz12 wrote:Steve traveled the first 2 hours of his journey at 40 mph and the remaining 3 hours of his journey at 80 mph. What is his average speed for the entire journey?

A. 60 mph
B. 56.67 mph
C . 53.33 mph
D. 64 mph
E. 66.67 mph
Total distance traveled by Steve= Distance traveled in 2 hours at 40mph + Distance traveled in 3 hours at 80mph = (2*40 + 3*80) miles = 320 miles
Total time for which Steve traveled = (2+3) hours = 5 hours.

Average speed for the entire journey = 320/5 mph = 64 mph.

The correct answer is D.
Rahul Lakhani
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
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by Abhishek009 » Fri Oct 22, 2010 4:50 am
pzazz12 wrote:Steve traveled the first 2 hours of his journey at 40 mph and the remaining 3 hours of his journey at 80 mph. What is his average speed for the entire journey?

A. 60 mph
B. 56.67 mph
C . 53.33 mph
D. 64 mph
E. 66.67 mph
Average speed = Total Distance travelled during the journey / Total time taken

There are 2 cases :

Case 1 :

Traveled the first 2 hours of his journey at 40 mph

Hence distance travelled is (2*40) 80 miles


Case 2 :

3 hours of his journey at 80 mph

Hence distance travelled is (3*80) 240 miles


Thus total distance travelled is : (240 + 80)320 miles.

Total time taken is : (2+3) 5 hours.

Hence Average speed is : 320 / 5 = 64mph.
Abhishek
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