singhmaharaj wrote:A certain meter records voltage between 0 volts and 10 volts, inclusive. If the average (arithmetic mean) value of 3 recordings on the meter was 8 volts, what was the smallest possible recording, in volts?
A) 2
B) 3
C) 4
D) 5
E) 6
Sum of values = (# of values)(mean)
So, sum of the 3 readings = (3)(
8) =
24
To MINIMIZE one of the readings, we must MAXIMIZE the other two readings.
The maximum reading is 10, so let two of the readings equal 10.
Since the sum of all 3 readings must be
24, the last remaining reading must equal
4
Answer:
C
Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
