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by swerve » Sun May 25, 2025 9:51 am

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The median of the set of values \(a, b, a+2b, a-3b, ab,\) and \(3b\) where \(a < b\) and \(b > 4,\) \(a > \dfrac{8}{3}\) is

A. \(\dfrac{(a-3b)}{2}\)

B. \(\dfrac{(a+3b)}{2}\)

C. \(\dfrac{(2a+b)}{2}\)

D. \(\dfrac{(2a-b)}{2}\)

E. \(\dfrac{(3a+b)}{2}\)

The OA is B
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