Brandon's average monthly use in 2001 =q min
Let Jodie's average monthly use in 2001=x minutes
Jodie's 2001 average monthly usage in minutes
i.e To check if q.x or q<x or q=x

Statement 1
From January to August = 8 months
$$1.5q=\frac{Total\ \min}{8}$$
and total months for 8 months =12q

If Jodie did not make any more calls from September to December or
$$x=\frac{12q}{12}=q\min$$
If Jodie made a call of at least 1 min from September to December then,
$$x=\frac{12q+4}{12}=\frac{12q}{12}+\frac{4}{12}=\left(q+\frac{1}{3}\right)\min$$
With the information in Statement 1
x is either equal to q or greater than q (with 1/3) but since we cannot decipher the logical position or value of x.

$$Statement\ 1\ is\ INSUFFICIENT.$$

Statement 2
From April to December, Jolie's average Monthly usage is 1.5q min
April to December = 9 months
$$Average=\ \frac{Total\ \min s\ spent\ on\ calls}{no\ of\ months\ }$$
$$1.5q=\ \frac{Total\ \min utes\ }{9}$$
Total minutes for 9 months =13.5q
If Jodie did not make any call from January to march then,
$$x=\frac{13.5q}{12}=1.125q\min
$$ $$If\ Jodie\ made\ at\ least\ one\ \min\ of\ call\ from\ Jan\ to\ Mar\ then$$
$$x=\frac{13.5q+3}{12}=\left(1.125q+\frac{1}{4}\right)\min$$
$$both\ cases\ x>q,\ Hence\ statement\ 2\ alone\ is\ SUFFICIENT.
$$ $$answer\ \ is\ Option\ B$$