BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Standard deviation problem

Expert replies
by jfranco23 » Mon Feb 16, 2009 5:12 pm
A certain characteristic in a large population has a distribution that is symmetric about the mean m. If 68% of the distribution lies one standard deviation d of the mean, what percent of the distribution is less than m+d?

A. 16%
B. 32%
C. 48%
D. 84%
E. 92%
Join the discussion
Source: — Problem Solving |

by billzhao » Mon Feb 16, 2009 5:39 pm
The answer is 84%. Am I correct?
Yiliang
Join the discussion

by jfranco23 » Mon Feb 16, 2009 5:51 pm
Yep, that is the answer, but how you get it?
Join the discussion

by billzhao » Mon Feb 16, 2009 6:17 pm
Refer to the graph attached.

According to the question, the shaded area (between m-d to m) + the percent between m and m+d is 68%. As the distribution is symmetric, we know that the percent betwenn m and m+d is 34%, as is shown.

Again as the distribution is symmetric, the percent on the left-hand-side of point m should be 50%.

So the percent of the distribution less than m+d is 50% + 34% = 84%

Answer is (D)
Attachments
graph.gif
Yiliang
Join the discussion