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Standard deviation of the volume?

Expert replies
by Ahmed MS » Wed Jun 15, 2011 11:49 pm
Some water was removed from each of 6 tanks. If standard deviation of the volumes of water at the beginning was 10 gallons, what was the standard deviation of the volumes at the end?

a. For each tank, 30% of water at the beginning was removed
b. The average volume of water in the tanks at the end was 63 gallons

I have been struggling to solve this problem. Please help me to solve this!

Cheers!
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Source: — Problem Solving |

by Anurag@Gurome » Thu Jun 16, 2011 1:32 am
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by Frankenstein » Thu Jun 16, 2011 1:37 am
Hi,
From(1):
if x1,x2,..,x6 are the values of quantities of water in the tanks and mean is m, SD is d, then after removing 30% from each of the tanks, the values will be 0.7x1,0.7x2,...0.7x6 and the mean is 0.7m
new SD will be 0.7d = 0.7(10) = 7
Sufficient

From(2):avg. volume of water at the end is 63 gallons.
No info. about the volumes of the tanks
Not sufficient

Hence, A
Cheers!

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by Ahmed MS » Thu Jun 16, 2011 9:40 pm
Thanks Frankenstein! That is really smart and helpful answer!

Cheers!
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by amit2k9 » Fri Jun 17, 2011 3:07 am
a set be (1,2,3) with std dev = 1 (considering the deviation from the median only)
subtracting 30% from each will be 0.7( 1,2,3) meaning std dev * 0.7. Hence sufficient.

b no idea about the initial volume and the changed percentage.

Thus a is clean.
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