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\(\sqrt{16+16}= \)

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by M7MBA » Sat Jun 05, 2021 5:29 am
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\(\sqrt{16+16}= \)

(A) \(4\sqrt2\)
(B) \(8\sqrt2\)
(C) \(16\sqrt2\)
(D) \(8\)
(E) \(16\)

Answer: A

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Re: \(\sqrt{16+16}= \)

by Ian Stewart » Sat Jun 05, 2021 8:25 am
$$\sqrt{\left(16\ +\ 16\right)}=\ \sqrt{\left(2\right)\left(16\right)}\ =\ \sqrt{2\ }\sqrt{16}=\ 4\sqrt{2}$$
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