Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

speed takes 2 second longer to travel 1 kilometer

Expert replies
by Needgmat » Wed Sep 07, 2016 9:58 am
A car travelling at a certain constant speed takes 2 second longer to travel 1 kilometer that it would take to travel 1 kilometer at 75 kilometer per hours. At what speed in kilometers per hour, is the car traveling?

A) 71.5

B) 72

C) 72.5

D) 73

E) 73.5

OAB

Please explain.

Many thanks in advance.

Kavin
Join the discussion
Source: — Problem Solving |

by GMATGuruNY » Wed Sep 07, 2016 11:38 am
Needgmat wrote:A car travelling at a certain constant speed takes 2 second longer to travel 1 kilometer that it would take to travel 1 kilometer at 75 kilometer per hours. At what speed in kilometers per hour, is the car traveling?

A) 71.5

B) 72

C) 72.5

D) 73

E) 73.5
2 seconds longer per 1k = 150 seconds longer per 75k.
Since there are 3600 seconds in 1 hour, the additional time needed to travel 75k at the slower rate = 150/3600 = 1/24 hours.
Since the slower time is 1/24 longer than the faster time, the slower time is 25/24 of the faster time.
Time and rate are RECIPROCALS.
Since the slower time is 25/24 of the faster time, the slower rate is 24/25 of the faster rate:
(24/25)(75) = 72.

The correct answer is B.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion

by Needgmat » Fri Sep 09, 2016 2:31 am
2 seconds longer per 1k = 150 seconds longer per 75k.
Since there are 3600 seconds in 1 hour, the additional time needed to travel 75k at the slower rate = 150/3600 = 1/24 hours.
Since the slower time is 1/24 longer than the faster time, the slower time is 25/24 of the faster time.
Time and rate are RECIPROCALS.
Since the slower time is 25/24 of the faster time, the slower rate is 24/25 of the faster rate:
(24/25)(75) = 72.

The correct answer is B.
Hi GMATGuruNY ,

Thanks for your explanation.

Is there any other approach?

Many thanks in advance.

Kavin
Join the discussion

by GMATGuruNY » Fri Sep 09, 2016 3:47 am
Needgmat wrote:A car travelling at a certain constant speed takes 2 second longer to travel 1 kilometer that it would take to travel 1 kilometer at 75 kilometer per hours. At what speed in kilometers per hour, is the car traveling?

A) 71.5

B) 72

C) 72.5

D) 73

E) 73.5
Alternate approach:

(75 kilometers)/(1 hour) = (75 kilometers)/(3600 seconds) = (1 kilometer)/(3600/75 seconds) = (1 kilometer)/(48 seconds).

Since the car takes 2 seconds longer to travel 1 kilometer, the rate = (1 kilometer)/(50 seconds).

(1 kilometer)/(50 seconds) * (3600 seconds)/(1 hour) = 72 kilometers per hour.

The correct answer is B.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion

by NandishSS » Fri Sep 09, 2016 10:32 am
Needgmat wrote:A car travelling at a certain constant speed takes 2 second longer to travel 1 kilometer that it would take to travel 1 kilometer at 75 kilometer per hours. At what speed in kilometers per hour, is the car traveling?

A) 71.5

B) 72

C) 72.5

D) 73

E) 73.5

OAB

Please explain.

Many thanks in advance.

Kavin

Alternate approach:

We know that Speed=Dist/Time

So Given T1-T2=2 sec

T1=1/S1, T2=1/75

(1/S1)-(1/75) = 2/3600 hr

On simplification S1=72Km/hr

OA:B
Join the discussion

by Needgmat » Sat Sep 10, 2016 12:57 am
Alternate approach:

(75 kilometers)/(1 hour) = (75 kilometers)/(3600 seconds) = (1 kilometer)/(3600/75 seconds) = (1 kilometer)/(48 seconds).

Since the car takes 2 seconds longer to travel 1 kilometer, the rate = (1 kilometer)/(50 seconds).

(1 kilometer)/(50 seconds) * (3600 seconds)/(1 hour) = 72 kilometers per hour.

The correct answer is B.
Hi GMATGuruNY ,

Thank you so much for your explanation sir.

All clear.

Thanks,

Kavin
Join the discussion