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by vaibhav101 » Wed Aug 01, 2018 7:52 am
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Harry started a 6 mile hike with a full 10-cup canteen of water and finished the hike in 2 hours with 1 cup of water remaining. If the canteen leaked at the rate of 1 cup per hour and Harry drank 3 cups of water during the last mile, how many cups did he drink per mile during the first 5 miles of the hike?

A 4/5
B 5/6
C 1
D 6/5
E 5/4
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by Scott@TargetTestPrep » Fri Aug 10, 2018 5:35 pm
vaibhav101 wrote:Harry started a 6 mile hike with a full 10-cup canteen of water and finished the hike in 2 hours with 1 cup of water remaining. If the canteen leaked at the rate of 1 cup per hour and Harry drank 3 cups of water during the last mile, how many cups did he drink per mile during the first 5 miles of the hike?

A 4/5
B 5/6
C 1
D 6/5
E 5/4
Since Harry had 1 cup of water remaining for the 2-hour hike and the canteen leaked at the rate of 1 cup per hour, he actually drank 7 cups of water during the 6-mile hike, Since he drank 3 cups during the last mile, he drank 4 cups during the first 5 miles and thus he drank 4/5 cup of water per mile during the first 5 miles.

Answer: A

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by deloitte247 » Sun Aug 12, 2018 3:16 am
Total amount of water = 10 cups
Amount that leaked in 2 hours = no of hours * no of cup
= 2 * 1 = 2 cups
Amount drinkable = 10 - 2 = 8 cups.
Amount left after hike = 1 cup.
Thus Henry drank = 8 - 1 = 7 cups
He drank 3 cups during the last mile of the hike.
Therefore, Amount of water drank during the first 5 miles = 7 - 3 = 4 cups.
Amount of water per mile (for the first 5 miles)
$$=\frac{\ no\ of\ cups}{no.\ of\ miles}\ =\ \frac{4}{5}$$

Option A is correct.
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