Speed/Distance

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vaibhav101: Master | Next Rank: 500 Posts; Posts: 138; Joined: Mon May 01, 2017 11:56 pm; Thanked: 4 times

by vaibhav101 » Wed Jun 06, 2018 8:30 am

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A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time . On the way, however the train lost about 12.5 minutes while stopping at the stations. The speed of the car is

A 100 km/hr
B 110 km/hr
C 120 km/hr
D 130 km/hr
E 150 km/hr

Source: Beat The GMAT — Problem Solving | Wed Jun 06, 2018 8:30 am

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Scott@TargetTestPrep: GMAT Instructor; Posts: 8246; Joined: Sat Apr 25, 2015 10:56 amFollowed by: 29 members; Location: Los Angeles, CA; Thanked: 43 times

by Scott@TargetTestPrep » Fri Jun 08, 2018 10:24 am

vaibhav101 wrote:A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time . On the way, however the train lost about 12.5 minutes while stopping at the stations. The speed of the car is

A 100 km/hr
B 110 km/hr
C 120 km/hr
D 130 km/hr
E 150 km/hr

We can let r = the speed of the car, and thus 1.5r = the speed of the train. Since the actual travel time of the train (i.e., not including the stopping time) is 12.5/60 = 25/120 = 5/24 hour less than the travel time of the car, we can create the equation:

75/r = 75/(1.5r) + 5/24

Multiplying the equation by 24r, we have:

1800 = 1200 + 5r

600 = 5r

120 = r

Answer: C

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