Two numbers x and y (x>y) are such that their sum is equal to three times their difference.Then the value of 3xy/2(x^2-y^2) ?
1.2/3
2.1
3.4/3
43/2
5.none of these
1.2/3
2.1
3.4/3
43/2
5.none of these
x+y=3(x-y) ....given
(x+y)^2=3(x^2-y^2) .....multiplyin both sides by (x+y)
x^2 + y^2 +2xy=3x^2-3y2;
2xy=2x^2-2y^2;
xy/x^2-y^2=1
3xy/2(x^2-y^2)=3/2
Hence answer is 3/2 which is number 4.
