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by ketkoag » Thu Apr 30, 2009 10:55 am
If x > 0, then 1/[v(2x)+vx] =

A. 1/v(3x)
B. 1/[2v(2x)]
C. 1/(xv2)
D. (v2-1)/vx
E. (1+v2)/vx

this is a problem from sets, i couldn't get it. my ans: A
OA: D
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by tdadic84 » Thu Apr 30, 2009 11:03 am
i think this is a typo..and OA has to be A...please double check...
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by ketkoag » Thu Apr 30, 2009 8:23 pm
i am sure that this is what i have in my sets. i also think there is some thing missing or incomplete, might be the problem with the set..
anyways thanks for the reply..
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by dumb.doofus » Thu Apr 30, 2009 8:59 pm
Guys this is a much simpler problem than you think and the answer is indeed D :-)


Image

HTH
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by scoobydooby » Fri May 01, 2009 1:33 am
thats smart dumb.dufoos!

i had been thinking it was v and not the square root notation :). bet ketkoag and tdadic were also doing the same :)

ps: how do you write the sq. root notation without using the "^"?
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by dumb.doofus » Fri May 01, 2009 8:37 am
scoobydooby wrote:thats smart dumb.dufoos!

i had been thinking it was v and not the square root notation :). bet ketkoag and tdadic were also doing the same :)

ps: how do you write the sq. root notation without using the "^"?
Thanks buddy..

well, I use MS word for writing these equations.. and then upload that as an image here..
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