BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Solution Problem

Expert replies
by 2sun3 » Thu Jul 31, 2008 6:45 am
A chemist has 10 liters of a solution that is 10 percent nitric acid by volume. He wants to dilute the solution to 4 percent strength by adding water. How many liters of water must he add?

If you can give me written explanation behind the step of calculations that would be really helpful.

Thanks
Join the discussion
Source: — Problem Solving |

by sudhir3127 » Thu Jul 31, 2008 6:51 am
my answer is 15L of water...

do let me know if its right,. i will explain u ..
Join the discussion

by malolakrupa » Thu Jul 31, 2008 7:00 am
Let x be the total water that needs to be added .

Hence the final volume will be x + 10 as 10 is the initial voulme of the solution

Desired % of nitric acid is = 4 %

Hence the equation would result in

(x+ 10 ) * 0.04 + ( x + 9) = x + 10
0.04x + 0.4 + x+ 9 = x + 10
1.04x + 9.4 = x+ 10
0.04 x = 0.6
x = .6 / 0.04 = 60 / 4 = 15

Thanks,
Join the discussion

by VP_RedSoxFan » Thu Jul 31, 2008 7:02 am
If there are 10 L of solution and 10% is nitric acid, then you can say that 1 L is acid and 9 L of water. To have 1 L of acid by 4% of the solution, then you set up this equation:

1L acid/xL solution = 4%

Solve for x and you get 25 L of solution of which 1 L is acid and 24 L is water.

24 L - 9 L = 15L of water added.
Ryan S.
| GMAT Instructor |
Elite GMAT Preparation and Admissions Consulting
www.VeritasPrep.com

Learn more about me
Join the discussion

by sudhir3127 » Thu Jul 31, 2008 7:03 am
i did in a simpler way.. hope its usefull

10L and 10% is nitic acid ...which means 1 lts

now we have 2 make this 1 litre as 4% of the total solution.

hence it is 1/4%= 25lts..

Quantity of water to be added is 25L-10L = 15L.
Join the discussion

Thanks

by 2sun3 » Thu Jul 31, 2008 9:21 am
Thank you all for your help.

I'll opt for a shorter method as it is my head spins while doing maths. LOL

Let me see if i understood it. If my reasoning is wrong could you point it out to me.

10 liters of solution has 10% of nitric acid, we get 1 litre of nitric acid in 10 liters of solution by 10*10/100= 1

so to make 1 liters as 4% of the total solution 1/4%=25 liters (stating sudhir, which i understood)

since 25 liters is the solution we get for making it 4%, since we already had 10 liters, we need to substract 10 from 25 to get the liters of water added.
Join the discussion

by wmensah » Wed Mar 11, 2009 8:32 am
visit this blog
https://800gmatblog.zoxic.com/page/2

from the mixtures problem, you're taught how to use a table. I applied it to this problem and surprisingly I got the right answer. It was really easy too. Here:

amount % total
sol'n 10 10 100 (ie. 10 * 10)
water x-10 0 0
mixture x 4 4x

% for water is 0 because if he wants to dilute it then he probably wants to add something which doesn't have any of the chemicals in it. We don't know what the total mixture is, so we use x to represent it.

setting up an equation with the last column, we get
100 = 4x
therefore x = 25 (total amount/volume of the mixture)

and therefore water = 25-10 = 15.
Join the discussion