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Smallest possible value

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by Deepthi Subbu » Wed Nov 17, 2010 8:41 pm
If x and y are positive integers and x/y has a remainder of 5 , what is the smallest possible value of xy?


Here is understand that since the remainder is 5 , the smallest possible integer (y) should be 6 . I am not able to proceed further . This problem is taken from MGMAT.

The OA is 30
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by Rahul@gurome » Wed Nov 17, 2010 9:42 pm
Deepthi Subbu wrote:If x and y are positive integers and x/y has a remainder of 5 , what is the smallest possible value of xy?


Here is understand that since the remainder is 5 , the smallest possible integer (y) should be 6 . I am not able to proceed further . This problem is taken from MGMAT.

The OA is 30
You are in the right track.
To minimize xy, we have to minimize both of x and y.
Minimum value of y is 6 because if y < 6 we'll never get a remainder of 5.
Now the question is what is the minimum possible value of x for which x/6 has a remainder of 5. And we are looking at the answer! Minimum possible value of x is 5!

Thus, minimum possible value of xy is 5*6 = 30.
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by ymach3 » Thu Nov 18, 2010 1:24 am
oh, is it in the form, x=n*y+5, where n is any integer.

for x to be min, n=0. there fore x=5 and y=6..

xy=30

correct???
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