Line L passes through point (r,-s) and (t, u), is the slope of the line negative?
(1) r>t
(2) u>-s
want a easy way for this,please.
(1) r>t
(2) u>-s
want a easy way for this,please.
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yalanand wrote:I will go for C....both options are required because
Slope of line = (r-t) / (-s-u)
= (r-t)/-(s+u)
So slope of the line will be negative if
r-t > 0 and s+u > 0 (u>-s)
This is a clear and concise solution .. I was fretting with all unwanted facts and got confused. Thanksaj5105 wrote:This is what I was looking for !
yalanand wrote:I will go for C....both options are required because
Slope of line = (r-t) / (-s-u)
= (r-t)/-(s+u)
So slope of the line will be negative if
r-t > 0 and s+u > 0 (u>-s)
Slope = y1-y2/x1-x2yalanand wrote:I will go for C....both options are required because
Slope of line = (r-t) / (-s-u)
= (r-t)/-(s+u)
So slope of the line will be negative if
r-t > 0 and s+u > 0 (u>-s)
I agree. Even I think A is enough.welcome wrote:Do we really need to go for C. I think A is enough.
Please clarify. If given r,t,u, -s are holding the sign, then by basic number prop. u+s will be +ve anyways.
yalanand wrote:I still think its C....because r,t,u,s are all variables which can be +ve or -ve...
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