Six Countries

1) A cant send 41, for if A sent 41, A being second highest, the highest would have been greater than 41 and we would have > 75

so the highest is 41. we have 75-41=34 reps to be distributed between A and the other 4 countries. a way to do this would be arrange them in descending order as no countries have the same number of reps.

say A =10, we can have the arrangements as 41+ 10+9+8+5+2=75
say A= 9, we can have the arrangements as 41+9+8+7+6+4=75

not sufficient as A can be greater or less than 10.

2) A<12
say A=11, we can have 30+11+10+9+8+7=75
say A=9, we can have 40+9+8+7+6+5=75

not sufficient as A can be greater or less than 10

taking both statements together we can have the same examples used for statement 1.
not sufficient

hence E

dravv a number line


1 ----------2------------3--------------4-------------5----------6


6Min 7 .............. 41 =75


So A< 10


41 10 ............................ 6


A= 10


similarly another line you can get vvhere A 11


So E
Since you cannot prove either vvays on vvhat A is

Please explain "6min 7.....41=75" and what it means, specifically, the "6min7"

venmic wrote:dravv a number line


1 ----------2------------3--------------4-------------5----------6


6Min 7 .............. 41 =75


So A< 10


41 10 ............................ 6


A= 10


similarly another line you can get vvhere A 11


So E
Since you cannot prove either vvays on vvhat A is