Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl; then a second card is drawn. If the cards are drawn at random and if the sum of the numbers on the cards is 8, what is the probability that one of the two cards drawn is numbered 5 ?
A. 1/6
B. 1/5
C. 1/3
D. 2/5
E. 2/3
the only ways to get sum 8 is if we pick
2 ,6 or 6 ,2
3, 5 or 5, 3
4, 4 or 4, 4
I want to know why we don't count 4, 4 twice? this is essentially a combination problem so why not total combinations 6 rather than 5?
favorable outcome will remain 2 either ways 3, 5 or 5,3.
Please explain
A. 1/6
B. 1/5
C. 1/3
D. 2/5
E. 2/3
the only ways to get sum 8 is if we pick
2 ,6 or 6 ,2
3, 5 or 5, 3
4, 4 or 4, 4
I want to know why we don't count 4, 4 twice? this is essentially a combination problem so why not total combinations 6 rather than 5?
favorable outcome will remain 2 either ways 3, 5 or 5,3.
Please explain
