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SinP and CosP

Expert replies
by harsh.champ » Wed Feb 17, 2010 6:18 am
If SinP , CosP are the roots of the equation ax ^2 + bx + c = 0 then


(A)a + b + 2ac = 0
(B)a^2 + b^2 + 2ac = 0
(C)a - b + 2ac = 0
(D)a^2 - b^2 + 2ac = 0
(E)a^2 - b^2 = 0
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Source: — Problem Solving |

by shashank.ism » Wed Feb 17, 2010 6:32 am
harsh.champ wrote:If SinP , CosP are the roots of the equation ax ^2 + bx + c = 0 then


(A)a + b + 2ac = 0
(B)a^2 + b^2 + 2ac = 0
(C)a - b + 2ac = 0
(D)a^2 - b^2 + 2ac = 0
(E)a^2 - b^2 = 0
since SinP , CosP are the roots of the equation ax ^2 + bx + c = 0
so SinP + CosP = -b/a
SinP . CosP = c/a
(SinP + CosP)^2 = (SinP)^2 + (CosP)^2 + 2 SinP.CosP
b^2/a^2 = 1+2c/a --> b^2 = a^2 + 2a.c --> [spoiler]a^2 - b^2 +2a.c=0 Ans C[/spoiler]
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