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by eaakbari » Sat Mar 27, 2010 12:20 am
In a garden , there are 10 rows and 12 columns of mango trees. the distance between the two trees is 2 m and a distance of one meter is left from all sides of the boundary of the length of the garden is


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by thephoenix » Sat Mar 27, 2010 12:37 am
eaakbari wrote:In a garden , there are 10 rows and 12 columns of mango trees. the distance between the two trees is 2 m and a distance of one meter is left from all sides of the boundary of the length of the garden is


No answer choices as this is from a review prep book
24
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by eaakbari » Sat Mar 27, 2010 1:03 am
Thats exactly what my answer was too. But the answer in the book says 22. I just wanted to cross check. I think the book is wrong

My explanation is
If there r n objects to be placed at even distances, the number of gaps will be n-1

so in this question gaps 12-1 = 11

gap of 2 mts hence = 22

and then 2 metres of extra space , so 24
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by eaakbari » Sat Mar 27, 2010 1:04 am
This is what the book says which I cannot comprehend, I feel its wrong

Each row contains 12 plants.
leaving 2 corner plants, 10 plants in between have 10 * 2 meters and
1 meter on each side is left.
length = (20 + 2) m = 22m
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by sanju09 » Sat Mar 27, 2010 6:22 am
eaakbari wrote:In a garden , there are 10 rows and 12 columns of mango trees. the distance between the two trees is 2 m and a distance of one meter is left from all sides of the boundary of the length of the garden is


No answer choices as this is from a review prep book
First of all you are not correctly wording the question. What length the question really asks for? Is it along the rows or columns? Even if it's along the rows as length for more than breadth in a cerebral rectangle, the book's explanation is off beam, as there undeniably are 11 equal spacing of 2 each plus 1 on either side, [spoiler]24[/spoiler] my precious!
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by eaakbari » Sat Mar 27, 2010 10:30 am
Shall check the wording next time before posting.
Thanks Sanju
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