Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Simple Math problem

Expert replies
by AndyB » Sun Oct 09, 2011 3:38 am
Hello Everyone,

Anybody!!! Please help me in solving the below problem.

5) The relationship between x and y is given as:

x 0 1 2 3 4 5 6
y 0 10 40 90 160 250 360


If x=2.5, what will be the value of y??

a)45
b)62.5
c)65
d)67.5

I am not able to understand how to derive a relationship between x and y...and then use x=2.5 and then get the result of y.
Join the discussion
Source: — Problem Solving |

by Anurag@Gurome » Sun Oct 09, 2011 3:49 am
AndyB wrote:The relationship between x and y is given as:

x 0 1 2 3 4 5 6
y 0 10 40 90 160 250 360


If x=2.5, what will be the value of y?
y is nothing but 10 multiplied with the square of x.

Hence, for x = 2.5, y = 10*(2.5)^2 = 62.5

The correct answer is B.
Anurag Mairal, Ph.D., MBA
GMAT Expert, Admissions and Career Guidance
Gurome, Inc.
1-800-566-4043 (USA)

Join Our Facebook Groups
GMAT with Gurome
https://www.facebook.com/groups/272466352793633/
Admissions with Gurome
https://www.facebook.com/groups/461459690536574/
Career Advising with Gurome
https://www.facebook.com/groups/360435787349781/
Join the discussion

by parul9 » Sun Oct 09, 2011 4:45 am
B!
the relation is y = 10x^2
And then substitution of x = 2.5 gives y = 62.5
Join the discussion

by Abhishek009 » Sun Oct 09, 2011 5:59 am
AndyB wrote:Hello Everyone,

Anybody!!! Please help me in solving the below problem.

5) The relationship between x and y is given as:

x 0 1 2 3 4 5 6
y 0 10 40 90 160 250 360


If x=2.5, what will be the value of y??

a)45
b)62.5
c)65
d)67.5

I am not able to understand how to derive a relationship between x and y...and then use x=2.5 and then get the result of y.

0 = 0 * 10

10 = 1^2 * 10

40 = 2^2 * 10

90 = 3^2 * 10

160 = 4^2 * 10

250 = 5^2 * 10

360 = 6^2 * 10



So actually y = ( x^2 ) *10


hence when x = 2.5


Y = 2.5^2 * 10

y =>6.25
Abhishek
Join the discussion

by GmatMathPro » Sun Oct 09, 2011 7:02 am
AndyB wrote: 5) The relationship between x and y is given as:

x 0 1 2 3 4 5 6
y 0 10 40 90 160 250 360


If x=2.5, what will be the value of y?
The best thing here is just to be so familiar with the sequence of the first few perfect squares, that the relationship just jumps out at you. But what if it doesn't?

If you absolutely cannot see what the formula should be just by looking at it, you can use the following:

Write down the differences between successive y-values, and then write down the differences between those first differences:

y= 0 10 40 90 160 250 360
differences= 10,30,50,70,90,110.
2nd diff= 20,20,20,20,20,20

There is a rule that says if the second differences of a sequence are constant(in this case 20), then the sequence can be modeled by a quadratic equation(that is y=ax^2+bx+c). This would tell you that the formula definitely involves x^2, and hopefully you would be able to see the relationship from there. If you still can't, proceed as follows:

We know the formula is of the form y=ax^2+bx+c and that y=0 when x=0, so plug in these values:
0=a*0^2+b*0+c
0=c

we know c is zero, so it must be that y=ax^2+bx. Now plug in another set of values, x=1, y=10

10=a+b

and another set of values: x=2 y=40

40=4a+2b

Solving this system of equations gives a=10, b=0 so the model is y=10x^2.

But again, this should be a last resort because of the time involved.
Pete Ackley
GMAT Math Pro
Free Online Tutoring Trial
Join the discussion

by AndyB » Mon Oct 17, 2011 2:22 am
Thanks everybody guys...For your time..
Join the discussion

by GmatKiss » Mon Oct 17, 2011 3:49 am
IMO: B, wish to get such questions in the real CAT :D
Join the discussion