BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Simple Math problem

Expert replies
by AndyB » Sun Oct 09, 2011 3:38 am
Hello Everyone,

Anybody!!! Please help me in solving the below problem.

5) The relationship between x and y is given as:

x 0 1 2 3 4 5 6
y 0 10 40 90 160 250 360


If x=2.5, what will be the value of y??

a)45
b)62.5
c)65
d)67.5

I am not able to understand how to derive a relationship between x and y...and then use x=2.5 and then get the result of y.
Join the discussion
Source: — Problem Solving |

by Anurag@Gurome » Sun Oct 09, 2011 3:49 am
AndyB wrote:The relationship between x and y is given as:

x 0 1 2 3 4 5 6
y 0 10 40 90 160 250 360


If x=2.5, what will be the value of y?
y is nothing but 10 multiplied with the square of x.

Hence, for x = 2.5, y = 10*(2.5)^2 = 62.5

The correct answer is B.
Anurag Mairal, Ph.D., MBA
GMAT Expert, Admissions and Career Guidance
Gurome, Inc.
1-800-566-4043 (USA)

Join Our Facebook Groups
GMAT with Gurome
https://www.facebook.com/groups/272466352793633/
Admissions with Gurome
https://www.facebook.com/groups/461459690536574/
Career Advising with Gurome
https://www.facebook.com/groups/360435787349781/
Join the discussion

by parul9 » Sun Oct 09, 2011 4:45 am
B!
the relation is y = 10x^2
And then substitution of x = 2.5 gives y = 62.5
Join the discussion

by Abhishek009 » Sun Oct 09, 2011 5:59 am
AndyB wrote:Hello Everyone,

Anybody!!! Please help me in solving the below problem.

5) The relationship between x and y is given as:

x 0 1 2 3 4 5 6
y 0 10 40 90 160 250 360


If x=2.5, what will be the value of y??

a)45
b)62.5
c)65
d)67.5

I am not able to understand how to derive a relationship between x and y...and then use x=2.5 and then get the result of y.

0 = 0 * 10

10 = 1^2 * 10

40 = 2^2 * 10

90 = 3^2 * 10

160 = 4^2 * 10

250 = 5^2 * 10

360 = 6^2 * 10



So actually y = ( x^2 ) *10


hence when x = 2.5


Y = 2.5^2 * 10

y =>6.25
Abhishek
Join the discussion

by GmatMathPro » Sun Oct 09, 2011 7:02 am
AndyB wrote: 5) The relationship between x and y is given as:

x 0 1 2 3 4 5 6
y 0 10 40 90 160 250 360


If x=2.5, what will be the value of y?
The best thing here is just to be so familiar with the sequence of the first few perfect squares, that the relationship just jumps out at you. But what if it doesn't?

If you absolutely cannot see what the formula should be just by looking at it, you can use the following:

Write down the differences between successive y-values, and then write down the differences between those first differences:

y= 0 10 40 90 160 250 360
differences= 10,30,50,70,90,110.
2nd diff= 20,20,20,20,20,20

There is a rule that says if the second differences of a sequence are constant(in this case 20), then the sequence can be modeled by a quadratic equation(that is y=ax^2+bx+c). This would tell you that the formula definitely involves x^2, and hopefully you would be able to see the relationship from there. If you still can't, proceed as follows:

We know the formula is of the form y=ax^2+bx+c and that y=0 when x=0, so plug in these values:
0=a*0^2+b*0+c
0=c

we know c is zero, so it must be that y=ax^2+bx. Now plug in another set of values, x=1, y=10

10=a+b

and another set of values: x=2 y=40

40=4a+2b

Solving this system of equations gives a=10, b=0 so the model is y=10x^2.

But again, this should be a last resort because of the time involved.
Pete Ackley
GMAT Math Pro
Free Online Tutoring Trial
Join the discussion

by AndyB » Mon Oct 17, 2011 2:22 am
Thanks everybody guys...For your time..
Join the discussion

by GmatKiss » Mon Oct 17, 2011 3:49 am
IMO: B, wish to get such questions in the real CAT :D
Join the discussion