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Simple but complicated

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Source: — Data Sufficiency |
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by camitava » Mon Feb 25, 2008 8:17 am
moneyman,
product of the first 8 positive integers mean 8 * 7 * 6 * 5* 4* 3 * 2
= 2^3 * 7 * 6 * 2^2 * 3 * 2 = 2^6 * 3 * 5 * 6 * 7

with stmt-1, a can be 2, 4 and 8 with n = 6, 3 and 2. Not suff.

now stmt-2 is saying n = 6 and a^n is a multiple of 2^6 * 3 * 5 * 6 * 7. so it is obvious that a = 2
so imo b.
Correct me If I am wrong


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by moneyman » Mon Feb 25, 2008 8:26 am
The problem says that the product of the 8 integers is a multiple of a^n and not the other way around?? any suggestions??
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by camitava » Mon Feb 25, 2008 8:29 am
moneyman wrote:The problem says that the product of the 8 integers is a multiple of a^n and not the other way around?? any suggestions??
I sam not getting u maxx. the qs is saying abt -
the product of the first 8 positive integers is a multiple of a^n
and that's why it means 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 and te rest is explained in my previous post.
Correct me If I am wrong


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