If the integers a and n are greater than 1 and the product of the first 8 positive integers is a multiple of a^n then what is a?
(1)a^n=64
(2)n=6
OA is B
(1)a^n=64
(2)n=6
OA is B
Maxx
moneyman,
product of the first 8 positive integers mean 8 * 7 * 6 * 5* 4* 3 * 2
= 2^3 * 7 * 6 * 2^2 * 3 * 2 = 2^6 * 3 * 5 * 6 * 7
with stmt-1, a can be 2, 4 and 8 with n = 6, 3 and 2. Not suff.
now stmt-2 is saying n = 6 and a^n is a multiple of 2^6 * 3 * 5 * 6 * 7. so it is obvious that a = 2
so imo b.
