Agreeing with DanaJ, but using a slightly different method which might save time for those comfortable with Combinations.
Total number of arrangements possible for 5 numbers = 5! = 120.
For finding total number of selections where 2 & 4 occur together, lets take 2&4 and bundle it to form one number X. So, total number of arrangements possible for 1,3,5 & x = 4! = 24.
But X is made up of 2 numbers 2 & 4, thus, number of ways X can be formed = 2! = 2.
So, total number of arrangements in which 2 & 4 are adjacent = 24 * 2 = 48.
Hence, total number of arrangements in which 2 & 4 are not adjacent = 120 - 48 = 72.
Cheers,
Dubes